We use the formula for the limiting molar conductance of acetic acid:
\[
\Lambda_m = \Lambda_m ({NaCl}) + \Lambda_m ({HCl}) - \Lambda_m ({CH}_3{COONa})
\]
Substituting the given values:
\[
\Lambda_m = 126.4 + 425.9 - 91.0 = 390.5 \, {S cm}^2 \, {mol}^{-1}
\]
Thus, the limiting molar conductance of acetic acid is \(390.5 \, {S cm}^2 \, {mol}^{-1}\).