Question:

The length of the tangent drawn from the point \( \left(\frac{k}{4}, \frac{k}{3}\right) \) to the circle \( x^2 + y^2 + 8x - 6y - 24 = 0 \) is:

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The length of a tangent from an external point to a circle is given by: \[ L = \sqrt{h^2 + k^2 - r^2} \]
Updated On: Mar 19, 2025
  • \( 7 \)
  • \( 1 \)
  • \( 12 \)
  • \( 24 \)
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The Correct Option is B

Solution and Explanation

Using the tangent length formula from a point \( (h, k) \) to a circle: \[ L = \sqrt{h^2 + k^2 - r^2} \] After substituting values and solving, we obtain: \[ L = 1 \]
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