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the length of the tangent drawn from the point lef
Question:
The length of the tangent drawn from the point \( \left(\frac{k}{4}, \frac{k}{3}\right) \) to the circle \( x^2 + y^2 + 8x - 6y - 24 = 0 \) is:
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The length of a tangent from an external point to a circle is given by: \[ L = \sqrt{h^2 + k^2 - r^2} \]
AP EAMCET - 2024
AP EAMCET
Updated On:
May 15, 2025
\( 7 \)
\( 1 \)
\( 12 \)
\( 24 \)
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The Correct Option is
B
Solution and Explanation
Using the tangent length formula from a point \( (h, k) \) to a circle: \[ L = \sqrt{h^2 + k^2 - r^2} \] After substituting values and solving, we obtain: \[ L = 1 \]
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