The Lagrangian of a particle of mass \( m \) and charge \( q \) moving in a uniform magnetic field of magnitude \( 2B \) that points in the \( z \)-direction, is given by: \[ L = \frac{m}{2} v^2 + qB(x v_y - y v_x) \] where \( v_x, v_y, v_z \) are the components of its velocity \( v \). If \( p_x, p_y, p_z \) denote the conjugate momenta in the \( x, y, z \)-directions and \( H \) is the Hamiltonian, which of the following option(s) is/are correct?
1. Conjugate momenta:
The conjugate momenta are given by: \[ p_x = \frac{\partial L}{\partial v_x} = m v_x + q B y \] \[ p_y = \frac{\partial L}{\partial v_y} = m v_y - q B x \] \[ p_z = \frac{\partial L}{\partial v_z} = m v_z \] 2. Hamiltonian:
The Hamiltonian \( H \) is the Legendre transform of the Lagrangian: \[ H = p_x v_x + p_y v_y + p_z v_z - L \] Substituting for \( v_x, v_y, v_z \) and simplifying the expression, we get: \[ H = \frac{1}{2m} \left[ (p_x + q B y)^2 + (p_y - q B x)^2 + p_z^2 \right] \] which matches option (D).
3. Equations of motion:
The equations of motion follow from the Hamiltonian dynamics. For \( \frac{d x}{d t} \), we have: \[ \frac{d x}{d t} = \frac{\partial H}{\partial p_x} = \frac{1}{m} (p_x - q B y) \] which matches option (A). Similarly, for \( \frac{d p_x}{d t} \), we get: \[ \frac{d p_x}{d t} = -\frac{\partial H}{\partial x} = \frac{q B}{m} (p_y - q B x) \] which matches option (B). For \( \frac{d p_y}{d t} \), we get: \[ \frac{d p_y}{d t} = -\frac{\partial H}{\partial y} = -\frac{q B}{m} (p_x + q B y) \] which matches option (C). Thus, the correct answers are (B), (C), and (D).
Due to presence of an em-wave whose electric component is given by \( E = 100 \sin(\omega t - kx) \, NC^{-1} \), a cylinder of length 200 cm holds certain amount of em-energy inside it. If another cylinder of same length but half diameter than previous one holds same amount of em-energy, the magnitude of the electric field of the corresponding em-wave should be modified as:
A proton is moving undeflected in a region of crossed electric and magnetic fields at a constant speed of \( 2 \times 10^5 \, \text{m/s} \). When the electric field is switched off, the proton moves along a circular path of radius 2 cm. The magnitude of electric field is \( x \times 10^4 \, \text{N/C} \). The value of \( x \) is \(\_\_\_\_\_\). (Take the mass of the proton as \( 1.6 \times 10^{-27} \, \text{kg} \)).
In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by:
In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by:
“Why do they pull down and do away with crooked streets, I wonder, which are my delight, and hurt no man living? Every day the wealthier nations are pulling down one or another in their capitals and their great towns: they do not know why they do it; neither do I. It ought to be enough, surely, to drive the great broad ways which commerce needs and which are the life-channels of a modern city, without destroying all history and all the humanity in between: the islands of the past.”
(From Hilaire Belloc’s “The Crooked Streets”)
Based only on the information provided in the above passage, which one of the following statements is true?
As the police officer was found guilty of embezzlement, he was _________ dismissed from the service in accordance with the Service Rules. Select the most appropriate option to complete the above sentence.
A wheel of mass \( 4M \) and radius \( R \) is made of a thin uniform distribution of mass \( 3M \) at the rim and a point mass \( M \) at the center. The spokes of the wheel are massless. The center of mass of the wheel is connected to a horizontal massless rod of length \( 2R \), with one end fixed at \( O \), as shown in the figure. The wheel rolls without slipping on horizontal ground with angular speed \( \Omega \). If \( \vec{L} \) is the total angular momentum of the wheel about \( O \), then the magnitude \( \left| \frac{d\vec{L}}{dt} \right| = N(MR^2 \Omega^2) \). The value of \( N \) (in integer) is:
The figure shows an opamp circuit with a 5.1 V Zener diode in the feedback loop. The opamp runs from \( \pm 15 \, {V} \) supplies. If a \( +1 \, {V} \) signal is applied at the input, the output voltage (rounded off to one decimal place) is: