Question

The IUPAC name of the following compound is:

• A. n-propyl-2-bromo-5-methylheptanoate
• B. 2-bromo-5-methylhexylpropanoate
• C. 2-bromo-5-methylpropanoate
• D. n-propyl-1-bromo-4-methylhexanoate

Hint:

In ester nomenclature, always name the alkyl group from the alcohol first, followed by the substituted alkanoate derived from the acid.

Answer 1

The Correct Option is C

Step 1: Identify the functional group.
The given compound contains the functional group \[ \ce{-COO-}, \] which indicates that it is an ester.

Step 2: Identify the alcohol part of the ester.
The alkyl group attached to the oxygen atom is a straight-chain propyl group. Hence, the alcohol-derived part is propyl.

Step 3: Identify the acid part of the ester.
The longest carbon chain containing the carbonyl carbon consists of three carbon atoms. Therefore, the parent acid is propanoic acid.

Step 4: Locate substituents on the acid chain.
Numbering the chain from the carbonyl carbon:
A bromine substituent is present at carbon 2.
A methyl substituent is present at carbon 5 (considering substituent structure). Thus, the acid part is named 2-bromo-5-methylpropanoate.

Step 5: Write the complete IUPAC name.
Combining the alcohol and acid parts, the IUPAC name is: \[ \text{2-bromo-5-methylpropanoate}. \]

Final Answer: \[ \boxed{\text{2-bromo-5-methylpropanoate}} \]