Since pH = 3.19,
Let the solubility of C6H5COOAg be x mol/L.
Then,
Thus, the solubility of silver benzoate in a pH 3.19 solution is 1.66 × 10-6 mol/L. Now, let the solubility of C6H5COOAg be x' mol/L.
Then [Ag+]=x'M and [CH3COO-]=x'M
\(K_{sp}=[Ag^+][CH3COO^-]\)
\(K_{sp}=(x')^2\)
\(x'=\sqrt{K_{sp}}=\sqrt{2.5\times10^{-13}}=5\times10^{-7}\,mol/L\)
\(\therefore \,\frac{x}{x'}=\frac{1.66\times10^{-6}}{5\times10^{-7}}=3.32\)
Hence, C6H5COOAg is approximately 3.317 times more soluble in a low-pH solution.
What inference do you draw about the behaviour of Ag+ and Cu2+ from these reactions?
The equilibrium constant may be defined as the ratio between the product of the molar concentrations of the products to that of the product of the molar concentrations of the reactants with each concentration term raised to a power equal to the stoichiometric coefficient in the balanced chemical reaction.
The equilibrium constant at a given temperature is the ratio of the rate constant of forwarding and backward reactions.
Kequ = kf/kb = [C]c [D]d/[A]a [B]b = Kc
where Kc, indicates the equilibrium constant measured in moles per litre.
For reactions involving gases: The equilibrium constant formula, in terms of partial pressure will be:
Kequ = kf/kb = [[pC]c [pD]d]/[[pA]a [pB]b] = Kp
Where Kp indicates the equilibrium constant formula in terms of partial pressures.
Medium Kc/Kp values indicate optimum product formation.
The equilibrium constant is the ratio of the concentrations raised to the stoichiometric coefficients. Therefore, the unit of the equilibrium constant = [Mole L-1]△n.
where, ∆n = sum of stoichiometric coefficients of products – a sum of stoichiometric coefficients of reactants.