The inverse of a function: \(x=\sqrt{3y+9}\) is
- \(x^2-\frac{3}{2}\)
- \(\frac{1}{3}x^2\)
- -3x2+1
- \(\frac{1}{3}x^2\)-3
The Correct Option is D
Solution and Explanation
Top Questions on Types of Functions
- \(\text{ If the function } f : \mathbb{N} \to \mathbb{N} \text{ is defined as } f(n) = \begin{cases} n - 1, & \text{if } n \text{ is even} \\ n + 1, & \text{if } n \text{ is odd} \end{cases} \text{, then:}\)
(A) f is injective
(B) f is into
(C) f is surjective
(D) f is invertible
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Help her to write a command to add the Category column.
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