Shape | Possibility |
---|---|
Cube | Not possible |
Triangle | Possible |
Rectangle | Possible |
None of these | N/A |
Explanation:
1. Cube: For the intersection of two cubes to be another cube, every edge and face must perfectly align into another cube structure, a scenario which is not geometrically feasible unless the cubes are identical, which technically does count as an "intersection" in different contexts, but not in the conventional sense intended here.
2. Triangle: Possible when two cubes intersect along a plane that slices through corners or edges.
3. Rectangle: Possible if the intersection occurs along adjacent surfaces of both cubes.
4. None of these: This option serves as a catch-all for any other unexpected intersection shape.
Thus, the intersection of two cubes cannot form another cube. The correct answer is cube.
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\))
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$
Find the missing code:
L1#1O2~2, J2#2Q3~3, _______, F4#4U5~5, D5#5W6~6