The general equation of a line whose intercepts with the coordinate axes are equal is: \[ \frac{x}{a} + \frac{y}{a} = 1 \] where $a$ is the intercept on both axes. Simplifying this, we get the equation of the line: \[ x + y = a \] Since the line passes through the point $(2, 3)$, we substitute these values into the equation: \[ 2 + 3 = a \] Thus, $a = 5$. Therefore, the equation of the line is: \[ x + y = 5 \]
The correct option is (B) : \(x+y=5\)
Let the intercepts of the line with the coordinate axes be \(a\). Then the line passes through the points \((a, 0)\) and \((0, a)\).
The equation of a line in intercept form is \(\frac{x}{a} + \frac{y}{b} = 1\), where \(a\) is the x-intercept and \(b\) is the y-intercept.
Since the intercepts are equal, we have \(\frac{x}{a} + \frac{y}{a} = 1\), which simplifies to \(x + y = a\).
The line passes through the point \((2, 3)\). Substituting this point into the equation, we get:
\(2 + 3 = a\)
\(a = 5\)
Therefore, the equation of the line is \(x + y = 5\).
In the adjoining figure, TP and TQ are tangents drawn to a circle with centre O. If $\angle OPQ = 15^\circ$ and $\angle PTQ = \theta$, then find the value of $\sin 2\theta$. 
What is the angle between the hour and minute hands at 4:30?