Step 1: {Rewriting the equation}
Divide through by \( y \): \[ \frac{1}{y} (x + 2y^2) \frac{dy}{dx} = 1. \]
Step 2: {Find the integrating factor}
The integrating factor \( \mu(y) \) is determined by identifying the dependency on \( y \) and multiplying the equation by \( \frac{1}{y} \).
Step 3: {Verify integrating factor}
After multiplying, the left-hand side becomes exact. The integrating factor is \( \frac{1}{y} \), which matches option (D).
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \( f(x + y) = f(x) f(y) \) for all \( x, y \in \mathbb{R} \). If \( f'(0) = 4a \) and \( f \) satisfies \( f''(x) - 3a f'(x) - f(x) = 0 \), where \( a > 0 \), then the area of the region R = {(x, y) | 0 \(\leq\) y \(\leq\) f(ax), 0 \(\leq\) x \(\leq\) 2 is :