Question:
The integral \(∫_3^lx^3\) log(x) dx equals
The integral \(∫_3^lx^3\) log(x) dx equals
Updated On: Apr 27, 2024
- \(\frac{3^4}{4} [log(3)]\)
- \(\frac{3^4}{4} [log(3)-\frac{1}{4}]\)
- \(\frac{3^4}{4} [log(3)]+\frac{1}{16}\)
- \(\frac{3^4}{4} [log(3)=\frac{1}{4}]+\frac{1}{16}\)
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The Correct Option is D
Solution and Explanation
The correct option is(D): \(\frac{3^4}{4} [log(3)=\frac{1}{4}]+\frac{1}{16}\)
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