Question:

The increasing order of the density of alkali metals is

Updated On: Mar 4, 2024
  • Li < K < Na < Rb < Cs
  • Li < Na < K < Rb < Cs
  • Cs < Rb < Na < K < Li
  • Cs < Rb < K < Na < Li
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The Correct Option is A

Solution and Explanation

On moving downward in a group, density increases but the density of K is somewhat lesser than Na.
Thus, the order of density is Li < K < Na < Rb < Cs
Densities are
Li - 0.53 g/cc
Na - 0.97 g/cc
K-0.86 g/cc
Rb - 1.53 g/cc
Cs - 1.90 g/cc
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Concepts Used:

Group 1 Elements

Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkali metals are characterized by one s-electron in the valence shell of their atoms.

Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:

  • Lithium(Li)
  • Sodium(Na)
  • Potassium (K)
  • Rubidium (Ru)
  • Cesium (Cs)
  • Francium (Fr)

They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.

Electronic Configuration:

  • Alkali metals have one electron in their valence shell.
  • The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
  • They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).

This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.