Question:
The hydride ion $H^-$ is stronger base than its hydroxide ion $OH^-$. Which of the following reactions will occur if sodium hydride (NaH) is dissolved in water?
The hydride ion $H^-$ is stronger base than its hydroxide ion $OH^-$. Which of the following reactions will occur if sodium hydride (NaH) is dissolved in water?
Updated On: Aug 1, 2022
- $2H^-(aq)+ H_2O(l) \rightarrow H_2O+H_2+2e^-$
- $H^-(aq)+ H_2O(l) \rightarrow OH^-+H_2$
- $H^-+H_2O(l) \rightarrow$ No reaction
- None of the above
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The Correct Option is B
Solution and Explanation
Sodium hydride dissolved in water as
$ \hspace20mm NaH+H_2O \rightarrow NaOH+H_2$
or $\hspace15mm H^-(aq)+H_2O(/) \rightarrow OH^-+H_2$ $\uparrow$
In the above reaction hydride ion take proton from water molecule and hydrogen gas is evolved.
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Concepts Used:
Hydrides
The ones that are anions of a hydrogen atom are hydrides. Hydrogen can act or respond to different elements of the periodic desk. Nucleophilic, decreasing, and fundamental properties may be found in the interior of the chemicals of hydrogen, and hydride. Hydride compounds are devised with all factors of the periodic table, excluding a few noble gases. Hydrides are common compounds of hydrogen but with lesser electronegative elements.
Types of Hydrides:
Depending upon the evolution of a chemical bond and the elements that can act with the hydrogen atoms, there are three types of hydrides:
- Ionic Hydrides
- Covalent Hydrides
- Metallic or Interstitial Hydrides