A group 15 element forms \( d\pi - d\pi \) bond with transition metals. It also forms a hydride, which is the strongest base among the hydrides of other group members that form \( d\pi - d\pi \) bonds. The atomic number of the element is …….
The element must be from group 15 and form \( d\pi - d\pi \) bonds.
Possible candidates: N, P, As. - Phosphorus (\( P \)) forms \( d\pi - d\pi \) bonds.
- \( PH_3 \) is a strong base compared to \( AsH_3 \).
Atomic number of Phosphorus = 15.
In the circuit shown, assuming the threshold voltage of the diode is negligibly small, then the voltage \( V_{AB} \) is correctly represented by:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: