Question:

The hydride ion, $H^-$, is a stronger base than the hydroxide ion, $OH^-$. Which one of the following reactions will occur if sodium hydride (NaH) is dissolved in water?

Updated On: Aug 1, 2022
  • $\ce{H^{-} (aq) + H_2O(l) -> H_3O^{-} (aq)}$
  • $\ce{H^{-} (aq) + H_2O(l) -> OH^{-} (aq) + H_2 (g)}$
  • $\ce{H^{- } (aq) + H_2O(l) -> OH^{-} (aq) + 2H^{+} (aq) + 2e}$
  • $\ce{H^{-} (aq) + H2O(l) ->}$ No reaction
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The Correct Option is B

Solution and Explanation

In this reaction $H^-$ acts as bronsted base as it accepts one proton $(H^+)$ from $H_2O$ and for $H_2$.
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Concepts Used:

Hydrides

The ones that are anions of a hydrogen atom are hydrides. Hydrogen can act or respond to different elements of the periodic desk. Nucleophilic, decreasing, and fundamental properties may be found in the interior of the chemicals of hydrogen, and hydride. Hydride compounds are devised with all factors of the periodic table, excluding a few noble gases. Hydrides are common compounds of hydrogen but with lesser electronegative elements.

Types of Hydrides:

Depending upon the evolution of a chemical bond and the elements that can act with the hydrogen atoms, there are three types of hydrides:

  • Ionic Hydrides
  • Covalent Hydrides
  • Metallic or Interstitial Hydrides