Question:

The Henry�s law constant for $O_2$ dissolved in water is $4.34 \times 10^4$ atm at certain temperature. If the partial pressure of $O_2$ in a gas mixture that is in equilibrium with water is 0.434 atm, what is the mole fraction of $O_2$ in the solution?

Updated On: Jun 23, 2023
  • $1 \times 10^{-5}$
  • $1 \times 10^{-4}$
  • $2 \times 10^{-5}$
  • $1 \times 10^{-6}$
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The Correct Option is A

Solution and Explanation

Given, $K_{H}$ for $O _{2}$ dissolved in water $=4.34 \times 10^{4} \,atm$ $PO _{2} =0.434 \,atm$ $x\left(\right.$ mole fraction of $O _{2}$ in solution $)=?$ According to Henry's law, $P =K_{H} \times x $ $\frac{0.434}{4.34 \times 10^{4}} =x_{ O _{2}} $ $1 \times 10^{-5} =x_{ O _{2}}$ $\therefore$ Mole fraction of $O _{2}$ in water $=1 \times 10^{-5}$.
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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.