Question:

The height at which the weight of a body becomes $1 / 16^{\text {th }}$, its weight on the surface of earth (radius R), is

Updated On: May 4, 2024
  • 5R
  • 15R
  • 3R
  • 4R
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The Correct Option is C

Solution and Explanation

$\frac{ W _{ h }}{ W }=\frac{ mg }{ mg }=\left(\frac{ R }{ R + h }\right)^{2}=\frac{1}{16}$
$\therefore h =3\, R$
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].