Question:

The half-life period of Radium is 3 minutes. Its decay constant is:

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The decay constant \( \lambda \) is inversely related to the half-life period of a radioactive substance.
Updated On: Jan 6, 2026
  • \( 1.5 \, \text{minute}^{-1} \)
  • \( 0.693 \, \text{minute}^{-1} \)
  • \( 0.231 \, \text{minute}^{-1} \)
  • \( 0.5 \, \text{minute}^{-1} \)
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The Correct Option is B

Solution and Explanation

Step 1: Use the relation between half-life and decay constant. The half-life \( t_{1/2} \) is related to the decay constant \( \lambda \) by: \[ t_{1/2} = \frac{\ln 2}{\lambda} \] Substituting \( t_{1/2} = 3 \, \text{min} \), we find: \[ \lambda = \frac{\ln 2}{3} = 0.693 \, \text{minute}^{-1} \]
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