The given outcrop pattern on a flat topography represents:

Step 1: Recall key fold geometry concepts.
- Antiform: A fold that is convex upwards (limbs dip away from the hinge). Whether it is an anticline or not depends on the facing direction of strata.
- Synform: A fold that is concave upwards (limbs dip towards the hinge).
- Horizontal fold: Fold axis is horizontal; map pattern is parallel bands, not closure.
- Plunging fold: Fold axis is inclined (plunging into the ground); map pattern forms closures (elliptical or eye-shaped patterns) on a horizontal surface.
- Axial culmination/depression: Refers to local highs or lows of the hinge line, not the closure itself.
Step 2: Interpret the figure.
- The map pattern shows elliptical eye-shaped closures, which indicate a plunging fold.
- The fold axis is clearly drawn and is inclined toward both ends (not horizontal).
- The convex-up shape with outward-dipping limbs indicates an antiform.
Step 3: Eliminate wrong options.
- (A) Antiform with axial culmination $\Rightarrow$ would not show elliptical closures but rather a culmination structure. Not correct.
- (B) Horizontal fold $\Rightarrow$ would give parallel stripes in outcrop, not an eye pattern. Not correct.
- (D) Synform with axial depression $\Rightarrow$ would be concave upwards, inconsistent with the given antiform geometry. Not correct.
Step 4: Correct interpretation.
Thus, the fold shown is an antiform with a plunging hinge line $\Rightarrow$ a plunging antiform.
Final Answer:
\[
\boxed{\text{Plunging antiform}}
\]

While doing Bayesian inference, consider estimating the posterior distribution of the model parameter (m), given data (d). Assume that Prior and Likelihood are proportional to Gaussian functions given by \[ {Prior} \propto \exp(-0.5(m - 1)^2) \] \[ {Likelihood} \propto \exp(-0.5(m - 3)^2) \] 
The mean of the posterior distribution is (Answer in integer)
Consider a medium of uniform resistivity with a pair of source and sink electrodes separated by a distance \( L \), as shown in the figure. The fraction of the input current \( (I) \) that flows horizontally \( (I_x) \) across the median plane between depths \( z_1 = \frac{L}{2} \) and \( z_2 = \frac{L\sqrt{3}}{2} \), is given by \( \frac{I_x}{I} = \frac{L}{\pi} \int_{z_1}^{z_2} \frac{dz}{(L^2/4 + z^2)} \). The value of \( \frac{I_x}{I} \) is equal to 
Suppose a mountain at location A is in isostatic equilibrium with a column at location B, which is at sea-level, as shown in the figure. The height of the mountain is 4 km and the thickness of the crust at B is 1 km. Given that the densities of crust and mantle are 2700 kg/m\(^3\) and 3300 kg/m\(^3\), respectively, the thickness of the mountain root (r1) is km. (Answer in integer)