We are given the genotypes of the husband and wife for the ABO blood group system:
The ABO blood group system involves three alleles: IA, IB, and IO (or i). IA and IB are codominant, and both are dominant over IO.
1. Determine the possible gametes produced by each parent:
2. Use a Punnett square to find the possible genotypes of the children:
Wife's Gametes | ||
Husband's Gametes | IA | IO |
IA | IAIA | IAIO |
IB | IAIB | IBIO |
3. List the possible genotypes of the children:
All four genotypes are distinct. Therefore, there are 4 different possible genotypes.
4. Determine the phenotype (blood type) for each genotype:
5. List the possible phenotypes of the children:
Even though there are four possible genotypes, two of them (IAIA and IAIO) result in the same phenotype (Blood type A). The distinct phenotypes are A, AB, and B. Therefore, there are 3 different possible phenotypes.
Conclusion: There are 4 different genotypes and 3 different phenotypes possible among the children.
Comparing this with the options: The correct option is 4 genotypes; 3 phenotypes.
Given the genotypes:
Husband: IAIB (Blood group AB)
Wife: IAi (Blood group A)
Let’s perform a cross to determine the possible genotypes and phenotypes of their children.
IA (wife) | i (wife) | |
---|---|---|
IA (husband) | IAIA | IAi |
IB (husband) | IAIB | IBi |
Possible Genotypes:
Possible Phenotypes:
Thus, the correct answer is (B) : 4 genotypes; 3 phenotypes.
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