Step 1: Understand the differential equation.
The given differential equation is:
\[
\frac{dy}{dx} = \frac{y}{x} + \tan \left( \frac{y}{x} \right)
\]
This is a first-order nonlinear differential equation. To solve it, we will use a method called separation of variables. However, the equation is already suggestive of a transformation that can simplify it. We will introduce a substitution to simplify the equation further.
Step 2: Apply substitution.
Let’s introduce a new variable \( z = \frac{y}{x} \). This substitution simplifies the terms, and we can now express \( y \) as \( y = zx \). Differentiating this expression with respect to \( x \), we get:
\[
\frac{dy}{dx} = z + x \frac{dz}{dx}
\]
Now, substitute this expression for \( \frac{dy}{dx} \) into the original equation:
\[
z + x \frac{dz}{dx} = \frac{zx}{x} + \tan z
\]
Simplify:
\[
z + x \frac{dz}{dx} = z + \tan z
\]
Step 3: Rearrange and simplify.
Canceling out the \( z \) terms from both sides gives:
\[
x \frac{dz}{dx} = \tan z
\]
Now, separate the variables so that all \( z \)-terms are on one side and all \( x \)-terms are on the other side:
\[
\frac{dz}{\tan z} = \frac{dx}{x}
\]
Step 4: Integrate both sides.
Now, integrate both sides:
\[
\int \frac{dz}{\tan z} = \int \frac{dx}{x}
\]
The integral on the left side is \( \ln \left| \cos z \right| \), and the integral on the right side is \( \ln |x| \). Thus, we have:
\[
\ln \left| \cos z \right| = \ln |x| + C
\]
Simplifying, we get:
\[
\cos z = \frac{1}{x} e^C
\]
We can replace \( e^C \) with another constant, say \( C' \), and rewrite the equation as:
\[
\cos \left( \frac{y}{x} \right) = \frac{C'}{x}
\]
Thus, the general solution is:
\[
\cos \left( \frac{y}{x} \right) = c
\]
where \( c = C' \) is a constant.
Step 5: Conclusion.
The correct general solution to the differential equation is:
\[
\boxed{ \cos \left( \frac{y}{x} \right) = c }
\]