The given differential equation is \( 4xy + 12x + (2x^2 + 3)y' = 0 \).
First, we can rewrite the equation in a more standard form:
\( y' = -\frac{4xy + 12x}{2x^2 + 3} \).
This is a linear first-order differential equation. We can try separating the variables or use an appropriate substitution. After simplifying and solving the equation, we obtain the general solution:
\( (y + 3)(2x^2 + 3) = C \),
where \( C \) is the constant of integration.
The correct answer is \( (y + 3)(2x^2 + 3) = C \).
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.