Step 1: Understanding coefficient of performance (COP):
COP is a measure of the efficiency of a refrigerator and is defined as:
\[ COP = \frac{Q_L}{W} \] where \( Q_L \) is the heat extracted from the cold reservoir and \( W \) is the work input.
Step 2: Role of thermodynamic laws:
The second law of thermodynamics sets a fundamental upper limit on the efficiency (COP) of heat engines and refrigerators.
It states that no process is possible in which the sole result is the absorption of heat from a reservoir and its complete conversion into work. Hence, COP cannot be infinite or exceed the Carnot limit.
A hot plate is placed in contact with a cold plate of a different thermal conductivity as shown in the figure. The initial temperature (at time $t = 0$) of the hot plate and cold plate are $T_h$ and $T_c$, respectively. Assume perfect contact between the plates. Which one of the following is an appropriate boundary condition at the surface $S$ for solving the unsteady state, one-dimensional heat conduction equations for the hot plate and cold plate for $t>0$?

The following data is given for a ternary \(ABC\) gas mixture at 12 MPa and 308 K:

\(y_i\): mole fraction of component \(i\) in the gas mixture
\(\hat{\phi}_i\): fugacity coefficient of component \(i\) in the gas mixture at 12 MPa and 308 K
The fugacity of the gas mixture is _________ MPa (rounded off to 3 decimal places).
The internal energy of air in $ 4 \, \text{m} \times 4 \, \text{m} \times 3 \, \text{m} $ sized room at 1 atmospheric pressure will be $ \times 10^6 \, \text{J} $. (Consider air as a diatomic molecule)