Question:

The frequency of the rotor current of a 50 Hz, 2 pole induction motor is 2 Hz, determine the percentage slip.

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Slip in induction motors is an important parameter that helps in evaluating the motor's efficiency and performance.
Updated On: Apr 21, 2025
  • 1.2%
  • 2.4%
  • 3.8%
  • 6%
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The Correct Option is B

Solution and Explanation

The slip \( S \) in an induction motor is given by the formula: \[ S = \frac{f_s - f_r}{f_s} \times 100 \] Where: - \( f_s \) is the synchronous frequency, and - \( f_r \) is the rotor frequency. For a 50 Hz, 2-pole motor, the synchronous speed \( N_s \) is: \[ N_s = \frac{120 \times f_s}{P} = \frac{120 \times 50}{2} = 3000 \, \text{rpm}. \] The slip is calculated as: \[ S = \frac{50 - 2}{50} \times 100 = 2.4%. \]
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