Question

The force constants of two springs are $ k_{1} $ and $ k_{2} $ respectively. Both are stretched till their potential energies are equal. The forces $ f_{1} $ and $ f_{2} $ applied on them are in the ratio

• A. $ k_{1} : k_{2} $
• B. $ k_{2} : k_{1} $
• C. $ \sqrt{k_{1}} : \sqrt{k_{2}} $
• D. $ \sqrt{k_{2}} : \sqrt{k_{1}} $

Answer 1

The Correct Option is C

Energy of spring $U=\frac{1}{2} k x^{2}$ and force $f=k x$ From these two, we get $U=\frac{1}{2} k \frac{f^{2}}{k^{2}}=\frac{1}{2} \frac{f^{2}}{k}$ $ \because$ Energies are equal, therefore $\frac{f_{1}^{2}}{k_{1}}=\frac{f_{2}^{2}}{k_{2}}$ $ \Rightarrow \frac{f_{1}}{f_{2}}=\frac{\sqrt{k_{1}}}{\sqrt{k_{2}}}$