Step 1: Cyclic Polymerization.
The starting material undergoes a cyclic polymerization reaction. This type of reaction typically forms a cyclic structure that is a precursor for further transformations.
Step 2: Gatterman-Koch's Reaction.
This reaction involves the formylation of an aromatic compound. In this case, it adds a formyl group to the aromatic compound, which is a critical intermediate step in the transformation.
Step 3: Pomeranz-Fritsch's Reaction.
The Pomeranz-Fritsch's reaction leads to the formation of isquinoline from the reaction intermediate formed in step 2.
Step 4: Conclusion.
Thus, the correct sequence involves cyclic polymerization, Gatterman-Koch's reaction, and the Pomeranz-Fritsch's reaction. Hence, option (4) is correct.
Final Answer: \[ \boxed{\text{(4) (i) Cyclic polymerization, (ii) Gatterman-Koch's reaction, (iii) Pomeranz-Fritsch's reaction}} \]
The reaction is carried out by:
Which of the following amino compound(s) CANNOT be prepared by Gabriel phthalimide synthesis?
(A) n-Butylamine
(B) Alanine
(C) Aniline
(D) t-Butylamine
Choose the correct answer from the options given below:
The final product (D) in the above sequential reaction is:
The major product (P) in the following transformation is:
Above conversion is carried out using:
Match List-I with List-II and choose the correct answer:
Match List-I with List-II:
Who said this sentence –
Match List-I with List-II and choose the correct answer:
Match List-I with List-II and choose the correct answer: