Comprehension
The following table gives the number of candidates Appeared (App.) and Qualifies (Quali.) in ABC entrance examination from different zones (I - IV in different years from 2006 - 2011)
| Zone | I | II | III | IV | V | VI | ||||||
| Year | App. | Quali. | App. | Quali. | App. | Quali. | App. | Quali. | App. | Quali. | App. | Quali. |
| 2006 | 2989 | 575 | 2490 | 530 | 2540 | 430 | 2534 | 440 | 1008 | 130 | 2698 | 498 |
| 2007 | 2438 | 590 | 2899 | 520 | 2384 | 470 | 2653 | 450 | 1103 | 160 | 2798 | 610 |
| 2008 | 7534 | 608 | 2840 | 532 | 2053 | 502 | 2234 | 480 | 1143 | 190 | 2848 | 580 |
| 2009 | 6524 | 650 | 3600 | 560 | 2143 | 510 | 2468 | 500 | 1198 | 220 | 3008 | 490 |
| 2010 | 8746 | 632 | 3608 | 544 | 2340 | 544 | 2549 | 560 | 1208 | 240 | 2948 | 560 |
| 2011 | 8429 | 648 | 5432 | 612 | 2230 | 588 | 2630 | 580 | 1203 | 238 | 3048 | 534 |
Question: 1
The qualifying percentage from zone V is maximum in which of the following years?
The qualifying percentage from zone V is maximum in which of the following years?
Updated On: Sep 23, 2024
- 2010
- 2011
- 2009
- 2006
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The Correct Option is A
Solution and Explanation
\(2006 = \frac{130}{1008} = 12.9\)
\(2007 = \frac{160}{1103} = 14.5\)
\(2008 = \frac{190}{1143} = 16.62\)
\(2009 = \frac{220}{1198} = 18.36\)
\(2010 = \frac{240}{1208} = 19.86\)
\(2011 = \frac{238}{1203} = 19.78\)
So, 2010 is the year for which zone V is maximum.
So the correct option is (A)
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Question: 2
The total number of qualifying candidates in 2009 is what per cent less than that in 2011?
The total number of qualifying candidates in 2009 is what per cent less than that in 2011?
Updated On: Sep 23, 2024
- 8.21%
- 9.89%
- 6.89%
- 8.43%
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The Correct Option is A
Solution and Explanation
Total number of qualifying candidates in 2009 =
\(650 + 560 + 510 + 500 + 220 + 490\)
\(= 2930\)
total number of qualifying candidates in 2011 =
\(648 + 612 + 588 + 580+238+534\)
\(=3192\)
\(\%\) required = \(3192 - \frac{2930}{3192}\)
= \(\frac{262}{3192}\)
= 8.2\(\%\)
So the correct option is (A)
\(650 + 560 + 510 + 500 + 220 + 490\)
\(= 2930\)
total number of qualifying candidates in 2011 =
\(648 + 612 + 588 + 580+238+534\)
\(=3192\)
\(\%\) required = \(3192 - \frac{2930}{3192}\)
= \(\frac{262}{3192}\)
= 8.2\(\%\)
So the correct option is (A)
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Question: 3
Ratio between boys and girls for qualified and for appeared from zone IV in 2009 are 7 : 3 and 3 : 2 respectively. What is the approximate ratio between the boys qualified and girls appeared?
Ratio between boys and girls for qualified and for appeared from zone IV in 2009 are 7 : 3 and 3 : 2 respectively. What is the approximate ratio between the boys qualified and girls appeared?
Updated On: Sep 23, 2024
- 2 : 13
- 2 : 5
- 1 : 28
- 1 : 50
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The Correct Option is B
Solution and Explanation
2009:
Appeared
Boys = \(\frac{7}{10} \times 2468 = 1728\)
Girls = \(\frac{3}{10} \times 2468 = 740\)
Qualified
Boys =\(\frac{3}{5} \times 500 = 300\)
Girls = \(\frac{2}{5} \times 500 = 200\)
Ratio required = \(\frac{300}{740}\)
\(= 0.4\)
\(\frac{2}{5}\) approx
So the correct option is (B)
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Question: 4
In which of the following zones is there a continuous increase in the number of students appeared as well as qualified over the years?
In which of the following zones is there a continuous increase in the number of students appeared as well as qualified over the years?
Updated On: Sep 23, 2024
- Zone II
- Zone III
- Zone IV
- None of these
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The Correct Option is D
Solution and Explanation
Zone 1: not continuous increase
Zone 2: not continuous increase
Zone 3: not continuous increase
Zone 4: not continuous increase
Zone 5: not continuous increase
Zone 6: not continuous increase
Not in any zones there is continuous increase.
So the correct option is (D)
Zone 2: not continuous increase
Zone 3: not continuous increase
Zone 4: not continuous increase
Zone 5: not continuous increase
Zone 6: not continuous increase
Not in any zones there is continuous increase.
So the correct option is (D)
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Question: 5
The number of students appeared from zone V in 2008 and 2011 together is approximately what per cent less than that from zone II in 2007 and 2010 together?
The number of students appeared from zone V in 2008 and 2011 together is approximately what per cent less than that from zone II in 2007 and 2010 together?
Updated On: Sep 23, 2024
- 63.5%
- 50.2%
- 55.6%
- 60%
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The Correct Option is A
Solution and Explanation
Number of students appeared from zone V in 2008 and 2011 together =
1143 + 1203
= 2346
Number of students appeared from zone II in 2007 and 2010 together =
2899 + 3608
= 6507
\(\%\) required = \(6507 - \frac{2346}{6507}\)
= 63.55\(\%\)
So the correct option is (A)
1143 + 1203
= 2346
Number of students appeared from zone II in 2007 and 2010 together =
2899 + 3608
= 6507
\(\%\) required = \(6507 - \frac{2346}{6507}\)
= 63.55\(\%\)
So the correct option is (A)
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