The Gabriel phthalimide synthesis is a reaction used to prepare primary amines. In this reaction, phthalimide (an imide compound) is first deprotonated to form a phthalimide anion, which then reacts with an alkyl halide to give an N-alkyl phthalimide. This intermediate can then undergo hydrolysis to yield a primary amine.
The general steps are:
1. Phthalimide is treated with a base (such as potassium hydroxide) to form a phthalimide anion.
2. The phthalimide anion then reacts with an alkyl halide (R-X) to form the N-alkyl phthalimide.
3. Hydrolysis (using acidic or basic conditions) of the N-alkyl phthalimide leads to the formation of a primary aliphatic amine (R-NH\(_2\)).
Thus, the product of the Gabriel phthalimide synthesis is a primary aliphatic amine.
Option (A) Secondary aliphatic amine: Incorrect. The Gabriel synthesis produces primary amines, not secondary amines.
Option (B) Primary aliphatic amine: Correct. As explained, the reaction leads to the formation of a primary aliphatic amine.
Option (C) Aromatic primary amine: Incorrect. This method typically yields aliphatic primary amines, not aromatic primary amines.
Option (D) Tertiary aliphatic amine: Incorrect. The reaction does not result in the formation of tertiary amines.
Thus, the correct answer is (B) Primary aliphatic amine.
The acid formed when propyl magnesium bromide is treated with CO_2 followed by acid hydrolysis is:
The best reagent for converting propanamide into propanamine is:
Identify A and B in each of the following reaction sequence:
(a) \[ CH_3CH_2Cl \xrightarrow{NaCN} A \xrightarrow{H_2/Ni} B \]
(b) \[ C_6H_5NH_2 \xrightarrow{NaNO_2/HCl} A \xrightarrow{C_6H_5NH_2} B \]
Chlorobenzene to biphenyl