Question

The Fe-Fe bond length is 2.48Å, the radius of iron atom is

• A. 0.62 Å
• B. 1.24 Å
• C. 2.48 Å
• D. 3.96 Å

Hint:

In metallic bonding, the atomic radius is calculated as half the bond length between adjacent atoms in the structure.

Answer 1

The Correct Option is B

In a metallic crystal structure, the atomic radius is half of the bond length between two adjacent atoms. Given the Fe-Fe bond length of 2.48 Å, we can calculate the atomic radius of iron as follows: \[ \text{Atomic Radius} = \frac{\text{Bond Length}}{2} = \frac{2.48}{2} = 1.24 \text{ Å}. \] Thus, the correct radius of the iron atom is 1.24 Å.