
Step 1: Understanding the concept of local attraction correction. In a closed traverse, local attraction affects the bearings of stations influenced by external magnetic interference. If station A is free from local attraction, the correct bearings of other stations must be adjusted accordingly.
Step 2: Checking the bearing of CA. From the given table, - Fore bearing of CA = \(227^\circ\) - Back bearing of CA = \(49^\circ\) (which is \(227^\circ - 180^\circ\)) This confirms station A has no local attraction, so corrections need to be applied to BC.
Step 3: Correcting the bearing of BC. For an unaffected station, \[ \text{Back Bearing} = \text{Fore Bearing} \pm 180^\circ. \] Checking BC, \[ \text{Back Bearing of BC} = 277^\circ. \] Thus, \[ \text{Fore Bearing of CB} = 277^\circ. \]
Match List-I with List-II
| List-I | List-II |
|---|---|
| (A) Alidade | (III) Plain table surveying |
| (B) Arrow | (I) Chain surveying |
| (C) Bubble Tube | (II) Leveling |
| (D) Stadia hair | (IV) Theodolite surveying |
Choose the correct answer from the options given below:
Match List-I with List-II
| List-I | List-II |
|---|---|
| Type of correction | Formula used |
| (The symbols have their usual meaning) | |
| (A) Sag correction | (I) \( \pm L(1 - h/R) \) |
| (B) Pull correction | (II) \( -\frac{1}{24} \times \left(\frac{W}{P}\right)^2 \) |
| (C) Temperature correction | (III) \( \pm (T_f - T_s)L \) |
| (D) Mean sea level correction | (IV) \( \pm \frac{(P_l - P_s) \times L}{AE} \) |
Choose the correct answer from the options given below:
If A + B means A is the mother of B; A - B means A is the brother of B; A % B means A is the father of B, and A \(\times\) B means A is the sister of B, which of the following shows that P is the maternal uncle of Q?