
Step 1: Understanding the concept of local attraction correction. In a closed traverse, local attraction affects the bearings of stations influenced by external magnetic interference. If station A is free from local attraction, the correct bearings of other stations must be adjusted accordingly.
Step 2: Checking the bearing of CA. From the given table, - Fore bearing of CA = \(227^\circ\) - Back bearing of CA = \(49^\circ\) (which is \(227^\circ - 180^\circ\)) This confirms station A has no local attraction, so corrections need to be applied to BC.
Step 3: Correcting the bearing of BC. For an unaffected station, \[ \text{Back Bearing} = \text{Fore Bearing} \pm 180^\circ. \] Checking BC, \[ \text{Back Bearing of BC} = 277^\circ. \] Thus, \[ \text{Fore Bearing of CB} = 277^\circ. \]
Reciprocal levelling is performed for points P and Q by placing the same levelling instrument at A and B. The observations of staff readings are tabulated as below. 
If the Reduced Level (RL) of P is 115.246 m, then the true RL of Q, in m, is _______ (rounded off to 3 decimal places)
If A + B means A is the mother of B; A - B means A is the brother of B; A % B means A is the father of B, and A \(\times\) B means A is the sister of B, which of the following shows that P is the maternal uncle of Q?