Question:

The expected number of tosses until the first head appears, given that head occurs with probability $p$, is \(\underline{\hspace{1cm}}\).

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The geometric distribution models repeated trials until first success; its expectation is always $1/p$.
Updated On: Dec 29, 2025
  • $p/(1-p)$
  • $(1-p)/p$
  • $1/p$
  • $1/p^2$
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The Correct Option is C

Solution and Explanation

The experiment follows a geometric distribution where the probability of success (head) is $p$.
For a geometric random variable $X$ counting the number of trials until the first success:
$\mathbb{E}[X] = 1/p$.
Thus the expected number of tosses required to get the first head is $1/p$.
Final Answer: $1/p$
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