Question:

The escape velocity from earth is 11.2 km/s. If a body is to be projected in a direction making an angle 45^{\circ} to the vertical, then the escape velocity is

Updated On: Jul 19, 2024
  • 11.2×2km/s11.2 \times 2\, km/s
  • 11.2km/s11.2\, km/s
  • 11.2/2km/s11.2/ \sqrt 2\, km/s
  • 11.22km/s11.2 \sqrt 2 \,km/s
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The Correct Option is B

Solution and Explanation

Escape velocity does not depend on the angle of projection. Escape velocity will remain same. Hence, scape velocity is 11.2km/s11.2\,km/s .
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].