Question

The equivalent resistance of the network shown in figure between A and B is:

• A. 10 \(\Omega\)
• B. 20 \(\Omega\)
• C. 5 \(\Omega\)
• D. 15 \(\Omega\)

Hint:

When two resistors are in parallel, the equivalent resistance is always less than the resistance of the smallest resistor.

Answer 1

The Correct Option is D

Step 1: Understanding the arrangement of resistors.
The two 10 \(\Omega\) resistors are connected in parallel. The formula for the equivalent resistance of two resistors in parallel is given by: \[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} \] Substituting \( R_1 = R_2 = 10 \, \Omega \), we get: \[ \frac{1}{R_{eq}} = \frac{1}{10} + \frac{1}{10} = \frac{2}{10} \] \[ R_{eq} = \frac{10}{2} = 5 \, \Omega \]
Step 2: Conclusion.
The equivalent resistance of the network is \( 5 \, \Omega \), so the correct answer is (.