Question:
The equation of the circle with center at $ (2, -3) $ and radius $ 5 $ is:
The equation of the circle with center at $ (2, -3) $ and radius $ 5 $ is:
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Remember the standard form of a circle’s equation: $ (x - h)^2 + (y - k)^2 = r^2 $. Pay attention to signs.
Updated On: May 24, 2025
- $ (x - 2)^2 + (y + 3)^2 = 25 $
- $ (x + 2)^2 + (y - 3)^2 = 25 $
- $ (x - 2)^2 + (y - 3)^2 = 25 $
- $ (x + 2)^2 + (y + 3)^2 = 25 $
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The Correct Option is A
Solution and Explanation
Standard form of a circle:
$$
(x - h)^2 + (y - k)^2 = r^2
$$
Given: center $ (h, k) = (2, -3) $, radius $ r = 5 $
Substituting: $$ (x - 2)^2 + (y + 3)^2 = 5^2 = 25 $$
Given: center $ (h, k) = (2, -3) $, radius $ r = 5 $
Substituting: $$ (x - 2)^2 + (y + 3)^2 = 5^2 = 25 $$
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