Question

The energy stored in a coil of inductance 80 mH carrying a current of 2.5 A is:

• A. 1.25 J
• B. 0.75 J
• C. 0.25 J
• D. 0.50 J

Hint:

Remember, the energy stored in an inductor is proportional to the square of the current flowing through it.

Answer 1

The Correct Option is C

The energy stored in an inductor is calculated using the formula: \[ E = \frac{1}{2} L I^2 \] where \( L = 80 \, \text{mH} = 0.08 \, \text{H} \) and \( I = 2.5 \, \text{A} \). Plugging in the values, we get: \[ E = \frac{1}{2} \times 0.08 \, \text{H} \times (2.5 \, \text{A})^2 = 0.25 \, \text{J} \]