The energy equivalent of a substance can be found using Einstein's famous equation: \[ E = mc^2 \] where:
\( E \) is the energy,
\( m \) is the mass of the substance,
\( c \) is the speed of light (\( c = 3 \times 10^8 \, \text{m/s} \)).
Given:
\( m = 5 \, \text{g} = 5 \times 10^{-3} \, \text{kg} \).
Now, using the formula: \[ E = (5 \times 10^{-3}) \times (3 \times 10^8)^2 \] \[ E = 5 \times 10^{-3} \times 9 \times 10^{16} \] \[ E = 4.5 \times 10^{14} \, \text{J} \] Thus, the energy equivalent of 5 g of the substance is \( 4.5 \times 10^{14} \, \text{J} \).
The correct option is (C) : \(4.5×10^{14}\ J\)
To find the energy equivalent of a mass, we use Einstein’s mass-energy equivalence relation:
E = mc²
Given:
Now,
E = (5 × 10-3) × (3 × 108)²
= (5 × 10-3) × (9 × 1016)
= 4.5 × 1014 joules
✅ Correct Option: 4.5 × 1014 J
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):