Question:
The electronic configuration of four elements are 1. $ [ Xe ] 6x^1$
2. $ [ Xe ] 4 f^{ 14} \, 5d^1 \, 6s^2 $
3. $ [ A r ] 4s^2 \, 4p^5 $
4. $ [ A r ] 3d^7 \, 4s^2 $
Which one of the following statements about these elements is not correct?
The electronic configuration of four elements are 1. $ [ Xe ] 6x^1$
2. $ [ Xe ] 4 f^{ 14} \, 5d^1 \, 6s^2 $
3. $ [ A r ] 4s^2 \, 4p^5 $
4. $ [ A r ] 3d^7 \, 4s^2 $
Which one of the following statements about these elements is not correct?
Updated On: Jun 6, 2022
- 1 is a strong reducing agent.
- 2 is a d-block element
- 3 has high electron affinity.
- 4 shows variable oxidation state.
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The Correct Option is B
Solution and Explanation
$ [ Xe ] 4 f^{ 14} \, 5d^1 \, 6s^2 $ is not ad-block element. It is lutetium and is present in lanthanide series, so lutetium is a f block element.
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Concepts Used:
Haloalkanes and Haloarenes - Classification
Classification of Haloalkanes and Haloarenes are as follows:
Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:
These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;
- Monohaloalkane
- Dihaloalkane
- Trihaloalkane
Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)
This class includes:
- Alkyl halides or haloalkanes (R—X)
- Allylic halides
- Benzylic halides
Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond
This class includes:
- Vinylic halides
- Aryl halides