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the electric field vector oscillates according to
Question:
The electric field vector oscillates according to the equation
\(\overrightarrow E = 4sin[1.8y +(5.4×10^6)t]\hat k\)
. The equation of magnetic field vector is:
CUET (UG) - 2023
CUET (UG)
Updated On:
Feb 28, 2025
\(\overrightarrow B=1.33×10^{-8}sin [1.8y +(5.4×10^6)t]î\)
\(\overrightarrow B=4sin[1.8y+(5.4 \times 10^6)t]\hat j\)
\(\overrightarrow B=1.33×10^{-8} sin[1.8y+(5.4×10^6)t]\hat k\)
\(\overrightarrow B = 5sin [1.8y +(5.4×10^6)t]\hat j\)
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The Correct Option is
A
Solution and Explanation
The correct option is(A):
\(\overrightarrow B=1.33×10^{-8}sin [1.8y +(5.4×10^6)t]î\)
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