$\eta=-\frac{ nF E _{\text {cell }}}{\Delta H } \times 100$
$\eta=-\frac{n F E_{\text {cell }}}{\Delta S} \times 100$
$\eta=-\frac{ nFE _{\text {cell }}}{\Delta A } \times 100$
None of the above
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Solution and Explanation
Efficiency of fuel cell is $\eta=-\frac{ nFE _{\text {cell }}}{\Delta H } \times 100$. The thermodynamic efficiency of the fuel cell is the ratio of the electrical free energy to the enthalpy change of the reaction. $\eta=\frac{\Delta G }{\Delta H } \times 100$ Also, $\Delta G =- nFE _{\text {cell }}$
A device that converts chemical energy into electrical energy is called an electric cell. To an electric circuit, the battery provides the constant electromotive force.
Each cell comprises 2 half cells which are connected in series by a conductive electrolyte containing anions and cations:
One-half cell is made up of electrolyte and a negative electrode called an anion.
The other half cell is made up of electrolytes and a positive electrode called a cathode.
Redox reactions take place simultaneously.
While charging, cations are reduced at the cathode, and anions are oxidized at the anode.
Electrodes do not join each other as they are electrically connected by the electrolyte.