Question:

The effective atomic number for $\left[R h\left(H_{2} O\right)_{6}\right]^{3+}$ (at. no. for $R h$ is $45$ ) is

Updated On: May 15, 2024
  • 42
  • 45
  • 48
  • 54
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The Correct Option is D

Solution and Explanation

The effective atomic number for $\left[R h\left(H_{2} O\right)_{6}\right]^{3+}$
(atomic no. of $R h=45$ ) is $54$ .
Because rhodium is in oxidation state
$x+6 \times 0=+3$
$x=+3$
$R h^{3+}=45-3=42$
$42+12$ electrons from $6$ ligands
$\left(H_{2} O\right)=54$ electrons.
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.