Question:

The domain of the function $f(x) = {^{24- x}C_{3x-1}} + {^{40 -6x}C_{8x-10}} $ is ,

Updated On: Jun 23, 2023
  • {2, 3}
  • {1 , 2, 3}
  • {1 , 2, 3 , 4 }
  • None of these
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The Correct Option is A

Solution and Explanation

$^{24-x}C_{3x-1}$ is defined if, $ 24-x > 0, 3x-1 \ge0 $ and $24-x \ge3x-1 $ $ \Rightarrow x <24 , x \ge\frac{1}{3}$ and $ x \le \frac{25}{4}$ $ \Rightarrow \frac{1}{3} \le x \le \frac{25}{4} $ $^{40-6x}C_{8x-10}$ is defined if $ 40-6x > 0 , 8x -10 \ge 0 $ and $40-6x \ge8x -10 $ $\Rightarrow x < \frac{20}{3} , x \ge\frac{5}{4}$ and $ x \le \frac{25}{7}$ $ \Rightarrow \frac{5}{4} \le x \le \frac{25}{7} $ From (1) and (2), we get $\frac{5}{4} \le x \le \frac{25}{7} $ But 24 - x $\in$ N $\therefore$ x must be an integer, x = 2, 3. Hence domain (f) = {2, 3}.
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions