Question:

The domain of the function $f \left(x\right)=\frac{1}{\sqrt{\left\{sin\,x\right\}+\left\{sin\left(\pi+x\right)\right\}}}$ where $\{\cdot \}$ denotes fractional part, is

Updated On: Jun 23, 2023
  • $[0$, $\pi]$
  • $(2n + 1)\pi/2$, $n \in Z$
  • $(0$, $\pi)$
  • None of these
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The Correct Option is D

Solution and Explanation

$f \left(x\right)=\frac{1}{\sqrt{\left\{sin\,x\right\}+\left\{sin\left(\pi+x\right)\right\}}}$ $=\frac{1}{\sqrt{\left\{sin\,x\right\}+\left\{-sin\,x\right\}}}$ Now, $\left\{sin x\right\}+\left\{-sinx\right\} = \begin{cases} 0, & \text{if $sin\,x$ is integer} \\[2ex] 1, & \text{if $sin\,x$ is not integer} \end{cases}$ For$ f(x)$ to be defined, $\{sinx\} + \{-sinx\} \neq 0$ $\Rightarrow sinx \neq$ integer $\Rightarrow sinx \ne \pm1$, $0$ $\Rightarrow x \ne\frac{n\pi}{2}$ Hence, domain is $R-\left\{\frac{n\pi}{2}, n\in I\right\}$.
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions