Question:

The distance between the sun and the earth be $r$, then the angular momentum of the earth around the sun is proportional to

Updated On: Jul 29, 2022
  • $ \sqrt{r} $
  • $r^3/2$
  • $r$
  • None of these
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The Correct Option is A

Solution and Explanation

According to Kepler's third law $T^{2} \propto r^{3} $ $\Rightarrow T \propto r^{3 / 2}$ We have $\omega=\frac{2 \pi}{T}$ $ \therefore \omega \propto r^{-3 / 2}$ Now, $L=m r^{2} \omega $ $\Rightarrow L \propto r^{2} \times r^{-3 / 2}$ $ \therefore L \alpha r^{1 / 2}$
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Concepts Used:

Momentum

It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.

the momentum of an object is the product of mass of the object and the velocity of the object.

Momentum = mass • velocity

The above equation can be rewritten as

p = m • v

where m is the mass and v is the velocity. 

Momentum is a vector quantity and  the direction of the of the vector is the same as the direction that an object.