Question:

The displacement $ x $ of a body varies with time as $ x=-\frac{1}{3}{{t}^{2}}+16t+3 $ where $ x $ is in metre and t in second. The time taken by the body to come to rest is

Updated On: Feb 18, 2024
  • 12s
  • 24s
  • 30s
  • 36s
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

$ x=-\frac{1}{3}{{t}^{2}}+16t+3 $ Velocity, $ v=\frac{dx}{dt} $ $=\frac{d}{dt}\left( -\frac{1}{3}{{t}^{2}}+16t+3 \right) $ $=-\frac{2}{3}t+16 $ The body comes to rest, so $ v=0 $ i.e., $ -\frac{2}{3}t+16=0 $ $ \Rightarrow $ $ \frac{2}{3}t=16 $ $ t=\frac{16\times 3}{2} $ $=24\,s $
Was this answer helpful?
2
0

Concepts Used:

Speed and Velocity

The rate at which an object covers a certain distance is commonly known as speed.

The rate at which an object changes position in a certain direction is called velocity.

Difference Between Speed and Velocity:

Difference Between Speed and Velocity

Read More: Difference Between Speed and Velocity