Step 1: Recall formula for discharge.
\[
Q = \frac{\Delta \cdot A}{t}
\]
where, $\Delta =$ depth of water (m), $A =$ area (m$^2$), $t =$ time (s).
Step 2: Convert values.
Area = $2600 \, ha = 2600 \times 10^4 = 2.6 \times 10^7 \, m^2$.
Depth = $17 \, cm = 0.17 \, m$.
Time = $30 \, days = 30 \times 24 \times 3600 = 2.592 \times 10^6 \, s$.
Step 3: Substitute in formula.
\[
Q = \frac{0.17 \times 2.6 \times 10^7}{2.592 \times 10^6}
\]
\[
Q = 1.71 \, m^3/s
\]
Step 4: Conclusion.
Thus, the required discharge capacity is $1.71 \, m^3/s$.


