Question:

The discharge capacity required at the outlet to irrigate 2600 ha of sugarcane, having a kor depth of 17 cm and a kor period of 30 days, is:

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Always convert hectare to $m^2$ and days to seconds when calculating irrigation discharge.
Updated On: Sep 24, 2025
  • $1.71 \, m^3/s$
  • $2.3 \, m^3/s$
  • $14.7 \, m^3/s$
  • $0.18 \, m^3/s$
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The Correct Option is A

Solution and Explanation


Step 1: Recall formula for discharge.
\[ Q = \frac{\Delta \cdot A}{t} \] where, $\Delta =$ depth of water (m), $A =$ area (m$^2$), $t =$ time (s).

Step 2: Convert values.
Area = $2600 \, ha = 2600 \times 10^4 = 2.6 \times 10^7 \, m^2$.
Depth = $17 \, cm = 0.17 \, m$.
Time = $30 \, days = 30 \times 24 \times 3600 = 2.592 \times 10^6 \, s$.

Step 3: Substitute in formula.
\[ Q = \frac{0.17 \times 2.6 \times 10^7}{2.592 \times 10^6} \] \[ Q = 1.71 \, m^3/s \]

Step 4: Conclusion.
Thus, the required discharge capacity is $1.71 \, m^3/s$.

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