The dimension of mutual inductance is :
The dimension of mutual inductance is :
- [ML2T–2A–1]
- [ML2T–3A–1]
- [ML2T–2A–2]
- [ML2T–3A–2]
The Correct Option is C
Solution and Explanation
The correct answer is (C) : [ML2T–2A–2]
∵ U = \(\frac{1}{2}\) Mi²
⇒ [M] = \(\frac{[U]}{[i^2]}\) = \(\frac{ML^2T^{-2}}{A^2}\)
= [ML2T–2A–2]
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter