Question

The difference in angular momentum of electrons between two successive orbits of hydrogen atom is:

• A. $\dfrac{2h}{\pi}$
• B. $\dfrac{h}{2\pi}$
• C. $\dfrac{h}{\pi}$
• D. $\dfrac{nh}{2}$

Hint:

Bohr’s postulate: angular momentum is quantized as $n\hbar$.

Answer 1

The Correct Option is B

Step 1: Bohr’s quantization rule.
Angular momentum of electron in orbit $n$ is: \[ L = n \dfrac{h}{2\pi} \]
Step 2: Successive difference.
For two successive orbits: \[ L_{n+1} - L_n = \dfrac{h}{2\pi} \]
Step 3: Conclusion.
So, the difference is $\dfrac{h}{2\pi}$.