Question:

The derivative of \(\tan^{-1}\!\sqrt{\dfrac{1-\cos x}{1+\cos x}}\) with respect to \(x\) is:

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Use half-angle identities to simplify.
Updated On: Jan 5, 2026
  • \(1/4\)
  • \(1/2\)
  • 1
  • \(-1/2\)
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The Correct Option is B

Solution and Explanation

\[ \sqrt{\frac{1-\cos x}{1+\cos x}}=\tan\frac{x}{2} \Rightarrow y=\tan^{-1}\!\left(\tan\frac{x}{2}\right)=\frac{x}{2} \] \[ \frac{dy}{dx}=\frac12 \]
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