Question:

The density of a solution prepared by dissolving $120\, g$ of urea (mol. mass = $60\, u$) in $1000 \,g$ of water is $1.15\, g/mL$. The molarity of this solution is :

Updated On: Jul 29, 2022
  • $0.50\, M$
  • $1.78\, M$
  • $1.02\, M$
  • $2.05\, M$
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The Correct Option is D

Solution and Explanation

Molarity $= \frac{mols\, of\, solute}{volume \,of \,sol. \left( \ell\right)}$ $= \frac{120 \times1.15}{60 \times1120} \times1000 = 2.05\,M$
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Concepts Used:

Concentration of Solutions

It is the amount of solute present in one liter of solution.

Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.

Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).

Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage

Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.

Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.

Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.

Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.

Formality - It is the number of gram formula present in one litre of solution.