Question:

The density (in $g\, mL^{-1}$) of a $3.60\, M$ sulphuric acid solution that is $29\%\,H_2SO_4$ (Molar mass $= 98\, g mol^{-1}$) by mass will be

Updated On: Apr 2, 2024
  • $1.64$
  • $1.88$
  • $1.22$
  • $1.45$
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The Correct Option is C

Solution and Explanation

Let the density of solution be $???? Molarity of solution given $= 3.6$ i.e. 1 litre of solution contains 3.6 moles of $H_2SO_4$ or 1 litre of solution contains $3.6 ??98 \,gms$ of $H_2SO_4$ Since, the solution is 29% by mass. 100 gm solution contains 29 gm $H_2SO_4$ $\frac{100}{d}ml$ solution contains $29\, gm$ of $H_2SO_4$ 1000 ml solution contains $3.6 ??98 \,gm$ of $H_2SO_4$ $\therefore 3.6\times9.8=\frac{29\times d}{100}\times1000$ $d=1.22$ Hence, (3) is correct.
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Concepts Used:

Concentration of Solutions

It is the amount of solute present in one liter of solution.

Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.

Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).

Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage

Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.

Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.

Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.

Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.

Formality - It is the number of gram formula present in one litre of solution.