The decomposition of hydrocarbon follows the equation
\(k = (4.5 \times 10^{11} s^{-1})e^{-28000 \ K/T }\)
\(Calculate\ E_a\).
The given equation is
\(k = (4.5 \times 10^{11} s^{-1})e^{-28000 \ K/T }\) ..... (i)
Arrhenius equation is given by,
\(k = Ae^{-\frac {E_a}{RT}}\) ...... (ii)
From equation (i) and (ii), we obtain
\(\frac {E_a}{RT} =\frac { 28000\ k}{T}\)
\(E_a = R \times 28000 \ K\)
\(E_a = 8.314 \ J K^{-1} mol^{-1} \times 28000\ K\)
\(E_a = 232792 \ J \ mol^{-1}\)
\(E_a = 232.792\ kJ \ mol^{-1}\)
Rate law for a reaction between $A$ and $B$ is given by $\mathrm{R}=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}}$. If concentration of A is doubled and concentration of B is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction $\left(\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}\right)$ is
For $\mathrm{A}_{2}+\mathrm{B}_{2} \rightleftharpoons 2 \mathrm{AB}$ $\mathrm{E}_{\mathrm{a}}$ for forward and backward reaction are 180 and $200 \mathrm{~kJ} \mathrm{~mol}^{-1}$ respectively. If catalyst lowers $\mathrm{E}_{\mathrm{a}}$ for both reaction by $100 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Which of the following statement is correct?
"There is widely spatial variation in different sectors of work participation in India." Evaluate the statement with suitable examples.
Alexia Limited invited applications for issuing 1,00,000 equity shares of ₹ 10 each at premium of ₹ 10 per share.
The amount was payable as follows:
Applications were received for 1,50,000 equity shares and allotment was made to the applicants as follows:
Category A: Applicants for 90,000 shares were allotted 70,000 shares.
Category B: Applicants for 60,000 shares were allotted 30,000 shares.
Excess money received on application was adjusted towards allotment and first and final call.
Shekhar, who had applied for 1200 shares failed to pay the first and final call. Shekhar belonged to category B.
Pass necessary journal entries for the above transactions in the books of Alexia Limited. Open calls in arrears and calls in advance account, wherever necessary.
On $31^{\text {st }}$ March, 2024, following is the Balance Sheet of Bhavik Limited :
Bhavik Ltd.
Balance Sheet as at $31^{\text {st }}$ March 2024
I. Equity and Liabilities :
| Particulars | Note No. | $31-3-2024$ (₹) | $31-3-2023$ (₹) |
| 1. Shareholders funds | |||
| (a) Share Capital | 12,00,000 | 10,00,000 | |
| (b) Reserves and Surplus | 1 | 4,00,000 | 3,00,000 |
| 2. Non-current liabilities | |||
| Long-term borrowings | 2 | 6,00,000 | 10,00,000 |
| 3. Current Liabilities | 5,00,000 | 1,00,000 | |
| (a) Trade Payables | 3 | 3,00,000 | 4,00,000 |
| (b) Short-term provisions | |||
| Total | 30,00,000 | 28,00,000 |
II. Assets :
| 1. Non-current Assets | |||
| (a) Property, Plant and Equipment and Intangible Assets | |||
| Property plant and equipment | 4 | 19,00,000 | 15,00,000 |
| (b) Non-current Investments | 3,00,000 | 4,00,000 | |
| 2. Current Assets | |||
| (a) Inventories | 4,50,000 | 3,50,000 | |
| (b) Trade Receivables | 2,50,000 | 4,50,000 | |
| (c) Cash and Cash Equivalents | 1,00,000 | 1,00,000 | |
| Total | 30,00,000 | 28,00,000 |
Notes to Accounts :
| Note | Particulars | $31-3-2024$ (₹) | $31-3-2023$ (₹) |
| No. | |||
| 1. | Reserves and Surplus i.e. Balance in Statement of Profit and Loss | 4,00,000 | 3,00,000 |
| 2. | Long-term borrowings | ||
| 10% Debentures | 6,00,000 | 10,00,000 | |
| 3. | Short-term provisions | ||
| Provision for tax | 3,00,000 | 4,00,000 | |
| 4. | Property plant and equipment | ||
| Plant and Machinery | 21,50,000 | 16,00,000 | |
| Less : Accumulated Depreciation | 2,50,000 | 1,00,000 | |
| 19,00,000 | 15,00,000 |
Additional Information :
Calculate :
Chemical kinetics is the description of the rate of a chemical reaction. This is the rate at which the reactants are transformed into products. This may take place by abiotic or by biological systems, such as microbial metabolism.
The speed of a reaction or the rate of a reaction can be defined as the change in concentration of a reactant or product in unit time. To be more specific, it can be expressed in terms of: (i) the rate of decrease in the concentration of any one of the reactants, or (ii) the rate of increase in concentration of any one of the products. Consider a hypothetical reaction, assuming that the volume of the system remains constant. R → P
Read More: Chemical Kinetics MCQ