The decomposition of hydrocarbon follows the equation
\(k = (4.5 \times 10^{11} s^{-1})e^{-28000 \ K/T }\)
\(Calculate\ E_a\).
The given equation is
\(k = (4.5 \times 10^{11} s^{-1})e^{-28000 \ K/T }\) ..... (i)
Arrhenius equation is given by,
\(k = Ae^{-\frac {E_a}{RT}}\) ...... (ii)
From equation (i) and (ii), we obtain
\(\frac {E_a}{RT} =\frac { 28000\ k}{T}\)
\(E_a = R \times 28000 \ K\)
\(E_a = 8.314 \ J K^{-1} mol^{-1} \times 28000\ K\)
\(E_a = 232792 \ J \ mol^{-1}\)
\(E_a = 232.792\ kJ \ mol^{-1}\)
The decomposition of a compound A follows first-order kinetics. The concentration of A at time t = 0 is 1.0 mol L-1. After 60 minutes, it reduces to 0.25 mol L-1. What is the initial rate of the reaction at t = 0? (Take ln 2 = 0.693)
Bittu and Chintu were partners in a firm sharing profit and losses in the ratio of 4 : 3. Their Balance Sheet as at 31st March, 2024 was as follows:
On 1st April, 2024, Diya was admitted in the firm for \( \frac{1}{7} \)th share in the profits on the following terms:
Prepare Revaluation Account and Partners' Capital Accounts.
Chemical kinetics is the description of the rate of a chemical reaction. This is the rate at which the reactants are transformed into products. This may take place by abiotic or by biological systems, such as microbial metabolism.
The speed of a reaction or the rate of a reaction can be defined as the change in concentration of a reactant or product in unit time. To be more specific, it can be expressed in terms of: (i) the rate of decrease in the concentration of any one of the reactants, or (ii) the rate of increase in concentration of any one of the products. Consider a hypothetical reaction, assuming that the volume of the system remains constant. R → P
Read More: Chemical Kinetics MCQ